Program to selectively "du -sk" directories 3

[saw]

I'm would like to do a "du -sk *" of a directory and for each line that produces, if the size of the directory is greater than 800MB, do a "du -sk" of that directory, then continue. Since this seems to be something that needs to be "line-based" rather than "word-based", I thought that maybe AWK could do it. The du, of course, prints out the size and the folder path as in:

382856 work/abc
725659 work/def
1338763 work/ghi

I'd like to take each line, and if the number is greater than 800000, then do 'du -sk' of that subdirectory, then continue.
Would I do this best with AWK?

thanks,
Scott
saw@ternion.com

 

[vgersh99]

not sure what you're trying to do, but here's something to think about:

#!/bin/ksh
typeset -i sizeTHR=800000
du -sk * | while read s dir
do
   if (( $s >= $sizeTHR )) ; then
      du -sk "${dir}"
   fi;
done

vlad
+----------------------------+
| #include<disclaimer.h> |
+----------------------------+

 

[PHV]

Something like this ?
du -sk * | awk '{print;if($1>800000)system("du -sk "$2"/*")}'

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ222-2244

 

[saw]

Thanks Vlad and PH! Both ways work great.

Hey Vlad, how did you post your code in that cool "CODE" box?

thanks again,
Scott

 

[PHV]

To obtain this:

my code here

Type this:
[ignore]

my code here

[/ignore]

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ222-2244

 

[saw]

Thanks PH, too cool!

Here's what I ended up doing:

du -sk * | while read SIZE DIR
   do echo "$SIZE $DIR"
   if [ "$SIZE" -gt 800000 ]
      then du -sk $DIR/* | while read SUBSIZE SUBDIR
      do echo "   $SUBSIZE $SUBDIR"
      done
   fi
done

I apologize for this not ending up being, necessarily, an AWK thing. Thanks again, though, for everyone's help!

Scott