Processing a list 1

[zaxxon]

Hello,

I have a list like this:

A:
   5432112 awdawd
   89672235 egwegs
   33597 sesefs
B:
   8923746 efsqwf
   33333 uh23dd
   23666 uahwd3
C:
   76432 afug23d
   91222 iohiu2
   237215 ih232893
D:
   # and so on

I want to know which label contains the pattern "33333", ie. I would like to have printed "B:".

I already tried following with awk:

    awk '
    /^[A-Z]:/
    {
                      label = $1
                      while ( NR != 1 )
                      {
                           if ( $1 == "33333" )
                           {
                                 print label
                                 break
                           }
                           else
                           {
                                 getline
                           }
                      }
    }

It doesn't work..
Thanks for a hint/help in forward. If anyone has a simple solution in awk and or sed I would be very thankful.

Bye
Zaxxon

laters
zaxxon

 

[columb]

Exactly this is covered in full in the O'Reilly Sed and Awk book (which any serious sysadmin ought to own). The answer, and I hope I'm not breaking copyright, is

#!/bin/ksh
search=$1 # 33333 in your case
awk 'BEGIN { FS= "\n"; RS = ""}
$0 ~ /'"$search"'/ {print $0}' $2

Where the call to the script is

awkscript searchpattern file

Ceci n'est pas une signature
Columb Healy

 

[feherke]

Hi

awk '/^[A-Z]:/{l=$0}/33333/{print l}' /input/file

[gray]# or[/gray]

sed -n '/^[A-Z]:/h;/33333/{g;p}' /input/file

Tested with [tt]gawk[/tt] and GNU [tt]sed[/tt].

Feherke.

http://rootshell.be/~feherke/

 

[zaxxon]

Thanks for the help.

laters
zaxxon