problem with ls -l script

[davemib]

i have a file called C which has the following information:

{n++;t+=$4};END{print "total number of files "n " " "total size"t
print $5, $9}

the code to run on command line is :

Ls –l | grep –v ^d | awk -f C

my problem is that it only prints one ordinary file out of the list. i have 19 oridinary files and only the last file is being printed. how can i make it print out the entire list cuz @ the moment the code which prints from the list is "print $5, $9"

can ne1 help me with this small problem

 

[CaKiwi]

Maybe

{print $5, $9; n++; t+=$5}
END{print "total number of files " n " total size "t}

CaKiwi

 

[davemib]

thanx CaKiwi it worked

thank you very much!!!!!!!!!!