Problem with cin >> ignoring input in a function

[mirirom]

hi,

i'm sure this is a pretty basic question. basically i have a function that's called within a loop. at the end of the function, i've placed

char c;
cout << "blah blah blah";
cin >> c;
cin.ignore(80, '\n');

however, the cin >> doesn't wait for the user's input. i've tested to see what's in the istream by printing out the int equivelant of char c. it's -1 every time.

any thoughts on this? many thanks in advance

..:: mirirom ::..

 

[uolj]

It depends on the code that comes before your little snippet. If you have a simple program:

#include <iostream>
using std::cout;
using std::cin;

int main()
{
    char c;
    cout << "blah blah blah";
    cin >> c;
    cin.ignore(80, '\n');
    cout << static_cast<int>(c);
}

it should work fine. One possibility is that the input stream still has data in it. Try posting a small but complete and compilable example that shows the problem.

 

[mirirom]

hi uolj,

thx for the reply. turns out the code was working fine. the function call in the loop was based on a conditional bool member, which at 2am i was trying to assign char data to.

after the bug fix, things are ok. thanks again...



..:: mirirom ::..