Problem with arrays and variable variables

[scorpion4377]

$$name[1] = 2;
// This will set a variable with a name of $name[1] to 2. But, I want to do this:

$($name)[1] = 2;

// I want it to make the variable to be an array. I know I can  use $$name = array(), but that's not very dynamic.

Thanks!

 

[kenrbnsn]

Did you look in the manual at

http://us2.php.net/manual/en/language.variables.variable.php

It is all explained there.

Ken