printing the line only when a value changes 1

[jkluesner]

Hello all,

I have a file reformated to finally look like this:

26 05 2008 2153 22 49.9985-107 52.0001
26 05 2008 2153 22 49.9985-107 52.0001
26 05 2008 2153 22 49.9985-107 52.0001
26 05 2008 2153 22 49.9986-107 52.0001
26 05 2008 2154 22 49.9985-107 52.0001
26 05 2008 2154 22 49.9985-107 52.0000
26 05 2008 2154 22 49.9985-107 52.0000
26 05 2008 2154 22 49.9986-107 52.0000
26 05 2008 2154 22 49.9986-107 52.0000

The next step I need to do is the take the first file from every minute (2153,2154) instead of having 60 files from each minute. Any suggestions? I will want a file just like the one above with only one value (the first) from each minute.

Thanks!

 

[Annihilannic]

awk '$4!=p;{p=$4}' inputfile

Annihilannic.

 

[Annihilannic]

I should explain: when the expression $4!=p evaluates to true, it will print the current input line. Then {p=$4} stores the current minute value in p so it can be used on the next line of input to check whether the minute matches the previous line.

Annihilannic.