Printing the last x num of fields in var length record

[Padre764]

Hello,

I am trying to create a nawk script to do the following: print the $1, $2, $(NF-1), $NF (basically print the first two fields and then the last two fields where the number of fields for each row varies). When I try to run this I get an error ("Trying to access field -1"). Any suggestions?

Thanks,
Padre

 

[aigles]

[tt]
nawk 'NF>1 {print $1,$2,$(NF-1),$NF}'
[/tt]

Jean Pierre.

 

[PHV]

Something like this ?
nawk '
NF>3{print $1,$2,$(NF-1),$NF;next}
{printf "NF=%d: %s\n",NF,$0}
' /path/to/inputfile
BTW be sure FS is correct for this file.

Hope This Help, PH.
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