Printing Filename in awk statement 2

[wilmington]

I need help getting the filename out with my print statement. I want to prefix each matching line with the filename.

I am reading through a list of files in $logs and printing lines with error: and matching date.
$log |awk -vdd=`date +%d` '{ if ($3==dd && /error:/) print }' >>test.out

how can I prefix the filename with each matching line of output.

any help would be great.
thanks

 

[dickiebird]

The name of the log file prefixed to each matching line ?
Would this work ?

$log |awk -vlg=$log -vdd=`date +%d` '{ if ($3==dd && /error:/) print lg$0 }' >>test.out

Dickie Bird (-)))

 

[vgersh99]

awk -vdd=`date +%d` '{ if ($3==dd && /error:/) print FILENAME, $0 }' $logs/* >>test.out vlad
+----------------------------+
| #include<disclaimer.h> |
+----------------------------+