Printing ASCII 1

[GirishGupta]

This isn't really a question specific to Borland C++ but it is C.

Does anyone know how to print ASCII code in C.

printf("\\97");

That doesn't work... Girish Gupta
girish@musicgoeson.com

 

[cyprus106]

i tried it on my compiler, it works fine for me. What doesn't work about it? You could try something like:
printf((char*)"\\97"
Cyprus

 

[GirishGupta]

The following code:

#include <stdio.h>

void main()
{
 printf(&quot;\\97\n&quot;);
 printf((char*)&quot;\\97\n&quot;);
 char i = getchar();
}

...outputs:

\97
\97

Any ideas why it doesn't work for me? Girish Gupta
girish@musicgoeson.com

 

[Pavlo]

Greetinx!

Its correct output so after this code has been executed really output will be '\97'.

For more infos see BorlandC++Builder Help on topic 'Escape sequences'. Happy programming!))

 

[GirishGupta]

I still don't understand how to it, or what I'm doing wrong... Girish Gupta
girish@musicgoeson.com

 

[Zyrenthian]

you could just go the easy route and do

char c = 97;
printf("%c = %d",c,(int)c);

Matt

 

[GirishGupta]

Brilliant!!! Thanks!

I've created the following:

#include <stdio.h>

void main()
{
 int i = 0;
 while (i<=256)
 {
  printf(&quot;%c = %d \n\n&quot;,i,(int)i);
  i++;
 }
 char g = getchar();
}

Girish Gupta
girish@musicgoeson.com