Printing a particular line 1

[Ambatim]

Is there any command in UNIX to print a particular line from a file.
I want to print only the second line from a file.

Any ideas ???

Thanks in Advance
Mallik

 

[raider2001]

You can do this with sed.

sed -n 2p file

 

[olded]

Ambatim:

how about using awk?

awk ' { if (NR == 2)
print $0 } ' < filename.txt

Regards,

Ed
Schaefer

 

[Einstein47]

there is always my favorite head | tail combination:
head -2 <filename> | tail -1

Although this is two commands, they seem to run faster than awk or sed. But any of these options should work for you. Einstein47
(Love is like PI - natural, irrational, endless, and very important.)

 

[MikeLacey]

&quot;sed -n 2p file&quot; ..... neat!
Mike
&quot;Experience is the comb that Nature gives us after we are bald.&quot;

Is that a haiku?
I never could get the hang
of writing those things.

 

[bigoldbulldog]

If you have a huge number of lines then better would be

sed -n '2p;2q' file

or (the same)

sed '2!d;2q' file

The 2q command tells sed to quit on that line, after the print command, so that the rest of the input is ignored.

Cheers,
ND

 

[MikeLacey]

Ok -- now don't think I'm being picky here (I probably am, but stil)

How would you print a range of lines using sed?
Mike
&quot;Experience is the comb that Nature gives us after we are bald.&quot;

Is that a haiku?
I never could get the hang
of writing those things.

 

[grega]

Mike, I've just been messing about with another thread here (printing the &quot;context&quot; of a grep result) and it seems, for example if you wanted to print lines 5-10, you would do sed -n 5,10p filename

Greg.