print section of file between two regular expressions (inclusive)

[viadisky]

I saw this from one of the awk one-liner examples. This will print a section of the file between these two regular expressions Iowa and Montana.

awk '/Iowa/,/Montana/'

How can I modify this to tell awk to start showing lines from Iowa up to the first blank line it will see?

awk '/Iowa/,/<1st blank line>/'

Definitely I can't use " " or "/n" because it will only print the line with Iowa and the next line to this.

Sorry if this is very basic question.

 

[viadisky]

Sorry for unnecessary posting my query, I realised now that I need this awk command.

awk '/Iowa/,/^$/'

Thanks anyway.

 

[feherke]

Hi

awk '/Iowa/,/^$/'

Feherke.

http://rootshell.be/~feherke/