Print output with variable leading zeros

[ranjit]

[tt]
I have a requirement to increment a number prefixed with variable leading zeros and print the output.

Input:
0012
000005
000099
0000100

Desired output:
0013
000006
000100
0000101

I'm fine if the output is required to be say 5 digits in length i.e using printf "%05\n" - the variable length per line is creating issues.

Thanks


[/tt]

 

[Mike042]

You can use variables in the printf as in:

length=6
printf "%0${length}d\n" 123

which produces:

000123

OR in Korn Shell you can typeset your variables as in:

typeset -Z4 my_var1=56
typeset -Z6 my_var2=432

echo "${my_var1} ${my_var2}"

produces:

0056 000432


I hope that helps.

Mike

 

[ranjit]

Thank you Mike

 

[ranjit]

[tt]
Mike,

Are you sure variable assignment within printf works?

$ cat test.awk
nawk 'BEGIN {

LENGTH=6
printf("%0${LENGTH}d\n", "123")
printf("%08d\n", "123")
}'

$ ./test.awk
{LENGTH}d
00000123

I didn't get the result you suggested.

Thanks
[/tt]

 

[PHV]

printf("%0"LENGTH"d\n", "123")

Hope This Helps, PH.
FAQ219-2884
FAQ181-2886

 

[fpmurphy]

The printf example is a shell example (man printf(1)), and does not work in n/g/awk.

 

[ranjit]

Thanks PHV