print out specific data plus name of file scanned 2

[jdespres]

I would like to print between the following:

"filename scanned"
#################
Media Log entries
#################

Print anything between these two........

##############
Tape Pool info
##############

And not print the top or bottom headers..

I have the following so far:

/Media Log entries/, /Tape Pool info/
!/Media Log entries/
!/Tape Pool info/

I just want to print the filename scanned and the data in between

Thanks....

Joe Despres

 

[PHV]

awk '/^#/{++h;next}!h||h==2' /path/to/input

Hope This Helps, PH.
FAQ219-2884
FAQ181-2886

 

[jdespres]

hhhmmmmmm...

I have other sections of data in the same files...

This code prints out the data in the first 2 sets of area's...


Thanks

Joe Despres

 

[jdespres]

The following does everything I need except for identifying the file name scanned...

nawk '/Media Log entries/, /Tape Pool info/' NBU_media_info.rpt.0[5][0123][0123456789]2010|egrep -v "Tape Pool info|Media Log entries|##"

Thanks....

Joe Despres

 

[p5wizard]

awk supplies a variable named FILENAME

see man page

HTH,

p5wizard

 

[PHV]

You wanted this ?

nawk 'FNR==1{print FILENAME;h=0}/^#/{++h;next}h==2' NBU_media_info.rpt.0[5][0123][0123456789]2010

Hope This Helps, PH.
FAQ219-2884
FAQ181-2886

 

[jdespres]

Looks like this works...........

for i in `ls NBU_media_info.rpt.0[5][0123][0123456789]2010`
do
echo "**************** $i ****************"
nawk '/Media Log entries/, /Tape Pool info/' $i | egrep -v "Tape Pool info|Media Log entries|##"
done

Thanks!

Joe Despres