print next line

[rhnaeco]

Hi,
I have a data file like this ($1 being the line number)
32....
33,8,8,8,8,8,8,8,8,8,8,8,8,8,8,245,230,120....
34,8,8,8,8,8,8,8,8,8,8,8,8,8,8,210,90,45....
35,200,200,200,200,200,200,200,200,105,214....
36....

what i want is for awk to:
if ($2 == "200") print next line only.

i have several of these '200' lines and want a file with just the lines that have suceeded each '200' line

i tried:
if ($2=="200") getline
print
but as you probably know, this printed every line after rather than just the one

hope you can help

rhnaceo

 

[feherke]

Hi

I do not understand your problem, but you need a block there :

awk '$2==200{getline;print}' /input/file

Feherke.

http://rootshell.be/~feherke/

 

[PHV]

if ($2=="200") [!]{[/!]
getline
print
[!]}[/!]

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ181-2886

 

[rhnaeco]

i guess it was just the formatting that needed seeing to.

cheers, that solved it

rhnaeco