Print all lines until reach specific phrase, then ignore rest of lines 1

[Ternion]

I'm trying to parse a BackupExec log file to simplify it down to just the system name and the amount backed up. I can grep out the needed lines, but the file also has the "verify" lines as well, which I don't need to see. How can I use awk (or something else) to print out everything that it reads until it reaches the phrase "Job Operation - Verify", then exit or just ignore the rest of the log file.

thanks for any help!
Scott
saw@ternion.com

 

[CaKiwi]

Something like

{print}
/Job Operation - Verify/{exit}


CaKiwi

 

[Ternion]

Thank you CaKiwi, that worked great! I knew there had to be a way for awk to work like that.

thanks again,
Scott