print all lines after trigger word

[columb]

I'm looking to output all lines from a log file after a certain trigger word. What I have so far is

last_occurence=$(grep -n $trigger $file|tail -1|cut -d : -f 1)
line_count=$(wc -l $file)
required_lines=$(expr $line_count - $last_occurence)
tail -$required_lines $file

but there must be a better way using sed or awk.

Any hints please?

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Columb Healy

 

[p5wizard]

awk -v trigger="${trigger}" '{
if (found) print
if ($0~trigger) found=1
}' /path/to/logfile

HTH,

p5wizard

 

[columb]

Sorry, my mistake, I forgot to say that it's all lines after the last occurence of the trigger word.

Ceci n'est pas une signature
Columb Healy

 

[p5wizard]

with an array:

awk -v trigger="${trigger} '{
if (found) a[found++]=$0
if ($0~trigger) found=1
}
END{
for (i=1;i<found;i++) print a
}'

HTH,

p5wizard

 

[columb]

Perfect!

Many thanks

Ceci n'est pas une signature
Columb Healy