print $4 to end of line?

[mikeboz]

I want to print $4 to the end of the line.

sample

32333r#1.mi 32333r#1 r#1 this is a description of the part


output:

this is a description of the part

 

[vgersh99]

echo "32333r#1.mi 32333r#1 r#1 this is a description of the part" | cut -d' ' -f4-

I had a very similar thread started a couple of hours ago on the related subject. I'd wonder how to do it purely in awk with NO NF/loop involved.

vlad

 

[mikeboz]

this is not so clean but,

awk '{print $4,$5,$6,$7,$8,$9,$10,$11,$12,$13,$14}' file1 > file2

it works, dont know what kind of problems it may cause.

 

[vgersh99]

this doesn't "cut" it - the poster needed a GENERIC solution - can't hard-wire the number of fields.

vlad

 

[flogrr]

Here is one way. Not silver bullet elegant, however!

nawk '{$1=$2=$3="";sub(" ",""print}' infile

Note that assigning the null to the first three fields does
not remove the FS associated with it, thus the sub
function call.

HTH


flogrr
flogr@yahoo.com