Pointer to member function

[aMember]

I need to find the address of a member function without making the function or the address identifier static.

Is this possible?

 

[Cagliostro]

class xclass
{
public:
void abd(){}
};


xclass xx;

void (xclass::*a)() = &xclass::abc;
(xx.*a)();


Ion Filipski

 

[aMember]

Thank you Ion!
Now if I wanted to print the address of the function, how would I do that?

 

[Cagliostro]

you can not do that using pure C++. But you can do it using asm:

xclass xx;
long y = 123;
void (xclass::*a)() = &xclass::abc;
__asm mov eax, a
__asm mov y, eax
cout<< (long) y<< endl;

By the way, why do you need that? You will never be able to use that address even if you know it.

Ion Filipski

 

[ArkM]

Ion, how about thia (pure C++:

class ExpandMe {}; // Prevents some confusions...
typedef unsigned long ulong; // (or char array;)
template <class Mfp> union Trick
{
  Mfp   ptr;
  ulong img;
  Trick(Mfp p)
  { if (sizeof ptr > sizeof img) throw ExpandMe();
    img = 0; ptr = p;
  }
  operator ulong() { return img; }
}; // Now include Ion::xclass dcl...
void (xclass::*a)() = &xclass::abd; // abd (as declared;)
typedef void (xclass::*memfunptr)();
...
typedef Trick<memfunptr> Xmfp;
cout << &quot;MemFunPtr is:&quot; << hex << Xmfp(a) << endl;

What's a wonderful platform independence...
Yes, of course, it's a vain enterprise: no need to print pointers (can we imagine a debug session in batch processing mode?...