pointer to a function

[Guest_imported]

hello, i try to use the clone function because i want my two processes to share data. Unfortunatelly, whatever i do, the compiler tells me:

passing arg 1 of `clone' from incompatible pointer type

The man page of clone is:

int clone(int (*fn)(void *), void *child_stack, int flags,
void *arg);

So "fn" IS A POINTER TO A FUNCTION, so i tried this:

int (*pf)(int);
pf=&my_function;
clone(&pf,...);

I also tried clone(pf,...);clone(*pf,...);...very bad things
And i'm always said the same thing!

Thanks for your help.

thomas

 

[dchoulette]

Your function must be a

int (*fn)(void *)

not a

int (*fn)(int);

Try:

int (*pf)(void *);
pf=&my_function;
clone(pf,...);

Of course my_function must also take a void * as argument and not an int.

You could also use the simple form:

clone(my_function, ...);