Plz help, why won't this println?

[zee3]

Ok i'm a newbie at java got everything to compile but it won't do any of the println statements when i execute it, and help would be appreciated


class Hashtable {

public long[] hash;

public static void main (String [] args){
Hashtable h = new Hashtable();
}

public Hashtable Hashtable(){

long[] hash = new long[6000];

hash[0] = 55;
int i = 0;

for (i = 0; i< 6000; i++){
System.out.println(hash[ i ]);}

return Hashtable();

}
}

 

[Hattusas]

That is because you are using a method same with your class's constructor name.

replace your method with this code below:

public Hashtable(){

long[] hash = new long[6000];

hash[0] = 55;
int i = 0;

for (i = 0; i< 6000; i++){
System.out.println(hash[ i ]);}

return ;
}

Salih Sipahi
Software Engineer.
City of Istanbul Turkey
s.sipahi@sahinlerholding.com.tr

 

[DJSmith]

Your setting your variable hash as an array of long's with a size of 6000. But you are only setting the first item to have a value (55).

Your println call is working but you are printing out 6000 lines of which the last 5999 are blank.

 

[Hattusas]

Makes no sense to me.
As first, the compiler creates a new instance of the class and the method is not visited.
Secondly if it were it should have printed the first value as &quot;55&quot; and the others as &quot;0&quot; because primitive variables like int,long,double,float,boolean have initial values. boolean --> false,others -- 0 IF they are defined in an ARRAY.

If you make a code like that

{
...
int a;
...
System.out.println(a);
...
}
It won't compile and will give the error local variable a may not have been initialized...


Salih Sipahi
Software Engineer.
City of Istanbul Turkey
s.sipahi@sahinlerholding.com.tr