I am trying to create an events calendar for a website i have a working calendar but would like to be able to link each day to a specific page if an event takes place on that day! I am using this code for the calendar:
I have used an online tutorial to help me create this but I am unable to figure out how to link each specific day if it is actually possible using this code! If anyone knows how or can point me in the direction of a better example to use i would appreciate it.
P.S. I have googled it and have not found anything helpful so far!
Code:
<html>
<head>
<title>PHP Calendar</title>
<style type="text/css">
<!--
.table.calendar {border: 1px solid #000000; border-collapse: collapse; color: #000000; background: #FFFFFF; }
.td.today { border: 1px solid white; color: #000000; background: #EFEFEF; font-weight: bold;}
.td.monthdays {border: 1px solid #434470; color: #000000; background: #FFFFFFF; }
.td.nonmonthdays { border: 1px solid white; color: #000000; background: #EFEFEF;}
-->
</style>
<body>
<?php
error_reporting('0');
ini_set('display_errors', '0');
// Gather variables from
// user input and break them
// down for usage in our script
if(!isset($_REQUEST['date'])){
$date = mktime(0,0,0,date('m'), date('d'), date('Y'));
} else {
$date = $_REQUEST['date'];
}
$day = date('d', $date);
$month = date('m', $date);
$year = date('Y', $date);
// Get the first day of the month
$month_start = mktime(0,0,0,$month, 1, $year);
// Get friendly month name
$month_name = date('M', $month_start);
// Figure out which day of the week
// the month starts on.
$month_start_day = date('D', $month_start);
switch($month_start_day){
case "Sun": $offset = 0; break;
case "Mon": $offset = 1; break;
case "Tue": $offset = 2; break;
case "Wed": $offset = 3; break;
case "Thu": $offset = 4; break;
case "Fri": $offset = 5; break;
case "Sat": $offset = 6; break;
}
// determine how many days are in the last month.
if($month == 1){
$num_days_last = cal_days_in_month(0, 12, ($year -1));
} else {
$num_days_last = cal_days_in_month(0, ($month -1), $year);
}
// determine how many days are in the current month.
$num_days_current = cal_days_in_month(0, $month, $year);
// Build an array for the current days
// in the month
for($i = 1; $i <= $num_days_current; $i++){
$num_days_array[] = $i;
}
// Build an array for the number of days
// in last month
for($i = 1; $i <= $num_days_last; $i++){
$num_days_last_array[] = $i;
}
// If the $offset from the starting day of the
// week happens to be Sunday, $offset would be 0,
// so don't need an offset correction.
if($offset > 0){
$offset_correction = array_slice($num_days_last_array, -$offset, $offset);
$new_count = array_merge($offset_correction, $num_days_array);
$offset_count = count($offset_correction);
}
// The else statement is to prevent building the $offset array.
else {
$offset_count = 0;
$new_count = $num_days_array;
}
// count how many days we have with the two
// previous arrays merged together
$current_num = count($new_count);
// Since we will have 5 HTML table rows (TR)
// with 7 table data entries (TD)
// we need to fill in 35 TDs
// so, we will have to figure out
// how many days to appened to the end
// of the final array to make it 35 days.
if($current_num > 35){
$num_weeks = 6;
$outset = (42 - $current_num);
} elseif($current_num < 35){
$num_weeks = 5;
$outset = (35 - $current_num);
}
if($current_num == 35){
$num_weeks = 5;
$outset = 0;
}
// Outset Correction
for($i = 1; $i <= $outset; $i++){
$new_count[] = $i;
}
// Now let's "chunk" the $all_days array
// into weeks. Each week has 7 days
// so we will array_chunk it into 7 days.
$weeks = array_chunk($new_count, 7);
// Build Previous and Next Links
$previous_link = "<a href=\"".$_SERVER['PHP_SELF']."?date=";
if($month == 1){
$previous_link .= mktime(0,0,0,12,$day,($year -1));
} else {
$previous_link .= mktime(0,0,0,($month -1),$day,$year);
}
$previous_link .= "\"><< Prev</a>";
$next_link = "<a href=\"".$_SERVER['PHP_SELF']."?date=";
if($month == 12){
$next_link .= mktime(0,0,0,1,$day,($year + 1));
} else {
$next_link .= mktime(0,0,0,($month +1),$day,$year);
}
$next_link .= "\">Next >></a>";
// Build the heading portion of the calendar table
echo "<table border=\"1\" cellpadding=\"2\" cellspacing=\"0\" width=\"300\" class=\"calendar\">\n".
"<tr>\n".
"<td colspan=\"7\">\n".
"<table align=\"center\">\n".
"<tr>\n".
"<td colspan=\"2\" width=\"75\" align=\"left\">$previous_link</td>\n".
"<td colspan=\"3\" width=\"150\" align=\"center\">$month_name $year</td>\n".
"<td colspan=\"2\" width=\"75\" align=\"right\">$next_link</td>\n".
"</tr>\n".
"</table>\n".
"</td>\n".
"<tr>\n".
"<td>S</td><td>M</td><td>T</td><td>W</td><td>T</td><td>F</td><td>S</td>\n".
"</tr>\n";
// Now we break each key of the array
// into a week and create a new table row for each
// week with the days of that week in the table data
$i = 0;
foreach($weeks AS $week){
echo "<tr>\n";
foreach($week as $d){
if($i < $offset_count){
$day_link = "<a href=\"".$_SERVER['PHP_SELF']."?date=".mktime(0,0,0,$month -1,$d,$year)."\">$d</a>";
echo "<td class=\"nonmonthdays\">$day_link</td>\n";
}
if(($i >= $offset_count) && ($i < ($num_weeks * 7) - $outset)){
$day_link = "<a href=\"".$_SERVER['PHP_SELF']."?date=".mktime(0,0,0,$month,$d,$year)."\">$d</a>";
if($date == mktime(0,0,0,$month,$d,$year)){
echo "<td class=\"today\">$d</td>\n";
} else {
echo "<td class=\"days\">$day_link</td>\n";
}
} elseif(($outset > 0)) {
if(($i >= ($num_weeks * 7) - $outset)){
$day_link = "<a href=\"".$_SERVER['PHP_SELF']."?date=".mktime(0,0,0,$month +1,$d,$year)."\">$d</a>";
echo "<td class=\"nonmonthdays\">$day_link</td>\n";
}
}
$i++;
}
echo "</tr>\n";
}
// Close out your table and that's it!
echo '<tr><td colspan="7" class="days"> </td></tr>';
echo '</table>';
?>
</body>
</html>I have used an online tutorial to help me create this but I am unable to figure out how to link each specific day if it is actually possible using this code! If anyone knows how or can point me in the direction of a better example to use i would appreciate it.
P.S. I have googled it and have not found anything helpful so far!