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Peer declares internal IP Freeswan Checkpoint

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2bean

Programmer
Aug 16, 2001
6
0
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DE
Hello,

I setup a linux box with freeswan 1.91 (incl. x509 patch) and want to connect to checkpoint (winnt).


192.168.x.y -- FreeswanGW (212.185.x.y) ---- Checkpoint(212.41.x.y) --- 172.32.x.y


I get the following message (freeswan site):

#113: initiating Main Mode
#113: we require peer to have ID '212.41.x.y', but peer declares '172.32.x.y'

The checkpoint peer advertise the private IP (server inside) as public IP (server outside).

How can I get off this trouble ?

OK, I know the internal IP adress '172.32.x.y' is not a valid Private-IP ala RFC 1918, but is that the problem ?

Thanks

Uwe
 
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