Pattern Matching

[hawkeye71]

Hi Folks:

I am trying to print a line if the pattern is not on that line.
I am writing all the statements in a script file.
I can make it work from the command line, but it did not work when i try to do the same from the script file.

For example, my input file is:
Hello World
Hello USA[1]
Hello USA[2] USA[3]

I only need to print when a line does not contain USA.
The following line works from command line:
awk '$2 !~/USA/ && $3 !~/USA/ {print $0}' <input file>

But when i put the same in the script file, it does not give the desired results. I have even tried to use the if condition, but the result stays the same.

In summary, I want to print a line if it does not contain a certain pattern.

Thanks,
Indiana

 

[vgersh99]

nawk -f usa.awk myFile.txt

#------------------ usa.awk
!/USA/

vlad
+----------------------------+
| #include<disclaimer.h> |
+----------------------------+

 

[hawkeye71]

VGersh99:

Do you want me to type
#include<disclaimer.h> in my script file.

In addition, I do not have access to nawk. When I type the &quot;nawk&quot; on command line, the response is &quot;nawk: Command not found.&quot;.

Thanks for help.

Thanks,
Indiana

 

[vgersh99]

No, PLS don't include my signature - it's not meant to be awk-proof
What OS are you on?

awk -f usa.awk myFile.txt

#------------------ usa.awk
!/USA/

 

[hawkeye71]

I am using HP-UNIX 11

The following worked for me:

{
if ($2 !~ /USA/ && NF != 0) {
if ($3 !~ /USA/) {
print $0}
}
}



Thanks,
Indiana

 

[tikual]

why don't use 'grep -v USA yourfile'? few keystrokes and more efficiency.

 

[vgersh99]

because it is an AWK forum?

vlad
+----------------------------+
| #include<disclaimer.h> |
+----------------------------+