passing shell string to awk 1

[tinoSWE]

Hi all,
any help would be very appreciated, cause I got stuck.

In my (bash) shell script, the string named "energy" has the value "double energy = 100;" (which is printed out correctly on the screen). I am using a shell "for" loop, so "100" is one of the possible values of the "i" variable.

I would like to pass the string "en" to the awk command below.
---
en=${base}${i}${end}
echo $en
awk 'NR==21{$0="en" }1' routInt.h > routInt.temp
---
in routInt.temp at line 21, it writes the letters "en" cause I don't know how to pass to awk the value of the string "en"... Can you help me?
Thanks in advance,

Martino

 

[feherke]

Hi

We have dozens of thread and one FAQ about passing shell variables in [tt]awk[/tt] script. Next time please search the existing threads and FAQs first.

awk "NR==21{$0=\"$en\"}1" routInt.h

[gray]# or[/gray]

awk 'NR==21{$0="'"$en"'"}1' routInt.h

[gray]# or[/gray]

awk -v en="$en" 'NR==21{$0=en}1' routInt.h

[gray]# or[/gray]

awk 'NR==21{$0=en}1' en="$en" routInt.h

[gray]# or[/gray]

export en
awk 'NR==21{$0=ENVIRON["en"]}1' routInt.h

Feherke.

http://free.rootshell.be/~feherke/

 

[tinoSWE]

thanks...
sorry for this.

M.

 

[PHV]

feherke, I'd replace this:
awk "NR==21{$0=\"$en\"}1" routInt.h
with this:
awk "NR==21{[!]\[/!]$0=\"$en\"}1" routInt.h

 

[feherke]

Hi

I missed that. Thank you.


Feherke.

http://free.rootshell.be/~feherke/