Passing pointer to array

[dd007]

I have a 2dimensional array and I only want to pass one row to a function. The array is setup as:
myArray[4][8];

I call the function:

status = functionx(myArray[j]); where j is the row

Fuction Prototype:
short functionx(short *myArray);

Function:
short functionx(short *myArray)

Is this correct? The program is very cpu intense and I trying to get all the performance out of the code as possible. I did not see much gain by changing the code
to use pointers. Just checking to see if I wrote the code correctly.

Thanks

 

[benlinkknilneb]

At first glance, that seems ok to me.

If you're trying to get all the performance possible, why not use a 1-dimensional array and do a little math? My understanding has always been that mathematical operations were quicker than array index manipulations.

For example:
int My1Array[9];

could really be the same as

int My2Array[3][3];

and

My1Array[row*3];

would be faster than

My2Array[row][0];

...at least, that's what I was always taught. Someone correct me if this isn't the case.

Ben
A programmer was drowning. Lots of people watched but did nothing. They couldn't understand why he yelled "F1!"

 

[ArkM]

dd007, strictly speaking, it's OK if myArray base type is short.
No need to excuse a pointer usage. We all on the C/C++ board, it's splendid!...