Pass variable into script from command line 1

[screwloose]

This solution from PHV worked great:

awk '/pag/{$1="";printf "%d)\t%s\n",++i,$0}' /path/to/input

I have been looking for an answer on the net, however, lacking any great skill with awk, how do I pass in "pag" as a variable? In ksh, of course, if I wanted to pass it from the command line I could do something like:

$0 variable

Which would pass variable into "pag" if it was $1, however that doesn't work in awk and I cannot find a way to do it.

Thanks!

 

[vgersh99]

awk -v pag=myVariableValue '$0 ~ pag {$1="";printf "%d)\t%s\n",++i,$0}' /path/to/input

vlad
+----------------------------+
| #include<disclaimer.h> |
+----------------------------+

 

[screwloose]

Thanks!