parsing exceptions 2

[columb]

I have a script which looks something like

#!/bin/ksh
for file in *
do
  # Skip known exceptions
  [[ $file = this ]] && continue
  [[ $file = that ]] && continue
  [[ $file = other ]] && continue
  process_file $file
done

Now I want to pass the exceptions as parameters. The best I can think of is

#!/bin/ksh
for file in *
do
  doit=TRUE
  for exception in $@
  do
    [[ $file = $exception ]] && doit=FALSE
  done
  [[ $doit = TRUE ]] && process_file $file
done

I hate using temporary variables (doit) and there must be a better way. Any suggestions?

Thanks

On the internet no one knows you're a dog

Columb Healy

 

[LKBrwnDBA]

Try this:

#!/bin/ksh
for file in *
do
  doit=`echo "$@"|grep -w $file"`
  [[ -z $doit ]] && process_file $file
done

----------------------------------------------------------------------------
The person who says it can't be done should not interrupt the person doing it. -- Chinese proverb

 

[columb]

That's great - I've amended it to

#!/bin/ksh
for file in *
do
  echo $@|grep -wq $file || process_file $file
done

On the internet no one knows you're a dog

Columb Healy

 

[PHV]

Another way:

#!/bin/ksh
for file in *
do
  for exception in $@
  do
    [[ $file = $exception ]] && continue 2
  done
  process_file $file
done

Hope This Helps, PH.
FAQ219-2884
FAQ181-2886

 

[feherke]

Hi

Not only nicer but faster too. Impressed. Again.

Feherke.

http://rootshell.be/~feherke/

 

[columb]

Ah, so continue can take a parameter - nice one PH!

On the internet no one knows you're a dog

Columb Healy