parse error in echo?

[jerusalm]

I keep getting a parse error saying looking for "(". Where am I going wrong?
The code is
If !$db die echo "mysql_errno: " mysql_errno()\n "mysql_error: " mysql_error()\n;
I'm testing to see if the connect to a MYSQL database was successful or not.

 

[sleipnir214]

I don't know how faithful your post is to the code you're actually trying to run, but the line of your code you've posted has a number of punctuation marks missing.

Something like:

If (!$db) die ("mysql_errno: ". mysql_errno()."\n". "mysql_error: ". mysql_error()."\n."

has a much better chance of actually running.

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[bw0lf]

When echo'ing, you have to remember to include periods(.) between quoted material and variables

i.e.

echo "Name: " . $name;

as opposed to:

echo "Name: " $name;


Also, escape sequences(\n for newlines) need to be inside of the quotes, as they are interpreted as part of a string.