Oracle Regex_Replace Patter Help

[BG12424]

I am trying to perform a regular expression to yield the following results:

would return:
company1.com

http://wwwcompany2.org

are the companies

using Oracle's regexp_replace function, but I'm struggling with the pattern syntax. Can anyone get me on the right track? I've been tackling this for quite a bit and struggling on how to structure it. I've been to the following sites for reference too. See below for the requirements.

http://regexlib.com/CheatSheet.aspx

http://www.regular-expressions.info/brackets.html

Rules for pattern:
1. Allows numbers and letters (a-zA-Z0-9)
2. Allows spaces (\s)
3. Allows Ampersands (&)
4. Allows Period (.), but only when it's followed by a space or end of line
5. Hyphens (-) and Forward Slashes (/) are to be replaced with spaces

select regexp_replace('company1.com

http://www.com-pany2.org

companies','<need help here>','') as dummy from dual;

Thanks so much in advance.

regards,
Brian


regards,
Brian

http://www.newleaftechinc.com