Open File in Current Directory

[Mungovan]

Hi.
I have a VB project that's located at C:\Documents and Settings\Owner\Desktop\Project.

I need to access a html file that will always be located in the same folder as the project.

However, I want the folder to be portable to other machines (that is, it may not always be located at the above path e.g c:\Project.

One of my comands is to output data to the html file and the code looks like this:
Open "C:\Documents and Settings\Owner\Desktop\Project\Print.html" For Output As ff

How can I make this a statement saying that the location is in the same folder as the project, but may have any path??

Can this be done?

Thanks,
D

 

[Som76]

Hello

Please use App.Path to get the cussrent application folder.

U can code as App.path & &quot;\&quot; & <filename>

Regards
Soumya

 

[Mungovan]

Cool, got it working in the code.

On a similar note:
I need to do something similar but in relation to the help file when F1 is pressed.
The path to the help file is placed inroject > Project Properties, and then enter the path of the .chm help file.

The app.path declaration doesn't work for this however.

Any ideas?

Thanks,
D