Obtain value from df

[sandeepmur]

Hi,

A df -k cmd in my HPUX machine gives the output :

/home/etbc01/KISS-EAI-R1 (/dev/VG_tbc/tibco_uat ) : 35510664 total allocated Kb
13786728 free allocated Kb
21723936 used allocated Kb
61 % allocation used

I need to obtain the value "61 %" from the above.. I have a script that obtains the free space.. can anyone please modify it for me ? here goes:

#!/usr/bin/sh

if (test $# -eq 0); then
df -k | awk '/\/home / || /\/opt /{
dir=$1;
getline;
free=$1;
print dir" "free
}'
else
df -k | awk '$1=="/"check {
dir=$1;
getline;
free=$1;
print free;
flag="true";
} END {
if (flag=="false") print -1
}' check="$1" flag="false"
fi

 

[xmb]

/allocation used/ { percent = $1 }

But that probably wont help you much out, How about..

getline; getline; percent = $1 " %"

. Mac for productivity
.. Linux for developement
... Windows for solitaire

 

[xmb]

#!/bin/sh

test $# -eq 0 && check=/home || check=$1

awk -v check="$check" '$1 ~ "/?" check " " {
  seen++
  dir = $1; getline; free = $1; getline; getline; percent = $1
  printf "%s -> %d free(%d)\n", dir, free, percent
} END { if (! seen) { print -1; exit 1 } }'

. Mac for productivity
.. Linux for developement
... Windows for solitaire