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NumberFormat() mask length 1

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pcorreia

Programmer
Feb 22, 2002
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I'm not very familiar with using NumberFormat() but I have to update some code written by someone else. What I need to do is this: given a decimal value (3.1 or 14.99), format the number to two decimal places. The code used to look like this:
Code:
  #NumberFormat(myVar,"_.__")#
but that started giving us errors when the numbers got bigger than 10. I changed it to this:
Code:
  #NumberFormat(myVar,"__.__")#
which works for now, but I'm looking for a way to make this work always, without having to guess how many digits there may be to the left of the decimal point. For example, in Perl I'd do this:
Code:
  printf("%.2f",$myVar);
and it would just output the number formatted to two decimal places, without me having to worry about how big the number might be.

Any suggestions?
 
Try the DecimalFormat() function:
Code:
#DecimalFormat(MyNum)#
Keep in mind, if there are more than two decimal places, the number will be rounded.

-Tek
 
Thanks, this is exactly what I was looking for.
 
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