Number of days since the beginning of the year 1

[claudeb]

hi,
i need a program that calculates the number of days since the beginning of the year.
example: 335 would be dec 20,2001 (for the year 2001)
thanks
claudeb

 

[GIGN]

Well, one way to do it simply is jsut to create an array which holds the number of days in each month.

var DateArray = new Array();
DateArray[0] = 31;
// etc


Then the next bits of code get the current month - this can be used as an index for this array. Then you add up the days before the current month, by adding together the elements 0 ---> currentMonth-1, then lastly add the current day, and there you have it. BB "Alright whatever man, I'll hook up the hair, but I aint touchin the ring...Cause I'm still a pla--yer"

 

[luciddream]

or you could use this function... its kinda bulky, but it does alot...


//returns an array of seconds, minutes, hours, day, month, year, dayof week, day of year, daylight savings time boolean.
//in that order. function works fine for day except the day that ends day light savings time. on the hour between 2 am and 2am
//on that day it will still say that it is daylight savings time... this is a bug that i was unable to work out.
Date.prototype.localtime = function()
{
var x = new Array();
var n = 0;
x.push(this.getSeconds());
x.push(this.getMinutes());
x.push(this.getHours());
x.push(this.getDate());
x.push(this.getMonth()+1);
x.push(this.getFullYear());
x.push(this.getDay());
var feb = (!(x[5]%4) && !(!(x[5]%100) && (x[5]%400)))?29:28;
switch(x[4])
{
case 1:
n = x[3];
break;
case 2:
n = 31+x[3];
break;
case 3:
n = 31+feb+x[3];
break;
case 4:
n = 62+feb+x[3];
break;
case 5:
n = 92+feb+x[3];
break;
case 6:
n = 123+feb+x[3];
break;
case 7:
n = 154+feb+x[3];
break;
case 8:
n = 184+feb+x[3];
break;
case 9:
n = 215+feb+x[3];
break;
case 10:
n = 245+feb+x[3];
break;
case 11:
n = 276+feb+x[3];
break;
case 12:
n = 306+feb+x[3];
break;
}
x.push;
var s = "04"
var t = "01";
var m = new Date(s+"/"+t+"/"+x[5]+" 02:00:01"
if(m.getDay() != 0)
{
t = 8-m.getDay();
t = "0"+t;
m = new Date(s+"/"+t+"/"+x[5]+" 02:00:01"
}
s = "10";
t = "31";
var f = new Date(s+"/"+t+"/"+x[5]+" 02:00:01"
if(f.getDay() != 0)
{
t = 31-f.getDay();
t = "0"+t;
f = new Date(s+"/"+t+"/"+x[5]+" 02:00:01"
}
if((this > m) &amp;&amp; (this < f))
{
x.push(1);
}
else
{
x.push(0);
}
return x;
} adam@aauser.com

 

[luciddream]

btw, you use it like this.

d = new Date();
array = d.localtime(); adam@aauser.com

 

[luciddream]

oops, also forgot... this only works in IE 5.5 and NS unless you add this function also...

Array.prototype.push = function(t)
{
this[this.length] = t;
}


adam@aauser.com

 

[GIGN]

This children is why we don't smoke crack - bJ. &quot;Alright whatever man, I'll hook up the hair, but I aint touchin the ring...Cause I'm still a pla--yer&quot;

 

[GIGN]

This children, is why we don't smoke crack - bJ. &quot;Alright whatever man, I'll hook up the hair, but I aint touchin the ring...Cause I'm still a pla--yer&quot;