Newby question on XSLT

[cardy]

I've been working my way thru' Steve Muench's excellent Building Oracle XML Apps book and was wondering why the following doesn't work as I think it should. I have an XML file, King.xml :

<?xml version=&quot;1.0&quot;?>
<?xml-stylesheet type=&quot;text/xsl&quot; href=&quot;KingToXML.xsl&quot;?>
<ROWSET>
<ROW>
<EMPNO>7839</EMPNO>
<ENAME>KING</ENAME>
</ROW>
</ROWSET>

The KingToXML.xsl stylesheet looks like :

<xsl:stylesheet version=&quot;1.0&quot; xmlns:xsl=&quot;

http://www.w3.org/1999/XSL/Transform&quot;>

<xslutput method=&quot;xml&quot; indent=&quot;yes&quot;/>
<xsl:template match=&quot;/&quot;>
<Invitation>
<To>
<xsl:value-of select=&quot;ROWSET/ROW/ENAME&quot;/>
<xsl:text> &amp; Family</xsl:text>
</To>
</Invitation>
</xsl:template>
</xsl:stylesheet>

The output I expect is :

<?xml version = '1.0' encoding = 'UTF-8'?>
<Invitation>
<To>KING &#38; Family</To>
</Invitation>

However when I try to view the King.xml file using Internet Explorer 5.5 all I get is :

& Family

Shouldn't Internet Explorer perform the transformation based upon the stylesheet and display the output as expected or am I misunderstanding the use of XSLT.

TIA

Cardy

 

[dianal]

Hello,
The problem with IE is that it cannot do client-side transforming when naming space

http://www.w3.org/1999/XSL/Transform

is used.
The solution is to use some server-side transforming.
The row <?xml-stylesheet type=&quot;text/xsl&quot; href=&quot;KingToXML.xsl&quot;?>
should be deleted from xml file.
For example the following ASP file will do the transformation:
<%
'Load the XML
set oXmlDoc = Server.CreateObject(&quot;MSXML2.DOMdocument&quot
oXmlDoc.async = false
oXmLDoc.load(Server.MapPath(&quot;king.xml&quot)

'Load the XSL
set oXslDoc = Server.CreateObject(&quot;MSXML2.DOMdocument&quot
oXslDoc.async = false
oXslDoc.load(Server.MapPath(&quot;KingToXML.xsl&quot)

'Transform the file
Response.Write(oXmlDoc.transformNode(oXslDoc))
%>

Hope this will help. D