pinkerton2002
Programmer
This is my code:
<?php
$sql="SELECT * FROM gjest";
$query=mysql_query($sql);
while($datas=mysql_fetch_array('$query')){ ?>
Navn:<?php
echo $datas["navn"]."<br>"; ?>
Hjemmeside:<?php
echo $datas["hjemmeside"]."<br>"; ?>
Dato:<?php
echo $datas["tid"]."<br>"; ?>
Melding:<?php
echo $datas["melding"]."<br>";
}?>
My error is this:
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource
<?php
$sql="SELECT * FROM gjest";
$query=mysql_query($sql);
while($datas=mysql_fetch_array('$query')){ ?>
Navn:<?php
echo $datas["navn"]."<br>"; ?>
Hjemmeside:<?php
echo $datas["hjemmeside"]."<br>"; ?>
Dato:<?php
echo $datas["tid"]."<br>"; ?>
Melding:<?php
echo $datas["melding"]."<br>";
}?>
My error is this:
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource