Need to read first 2000 bytes of a file and search/replace

[eholdo]

Hello,
using csh I need to read in the first 2000 bytes of a file, look for the expression (not including quotes)
"%PDF" and split the file before into one file, and the string plus what follows into a separate file, then replace the first 2000 bytes of the original file with the second file (the one that starts with "%PDF".

Help.... running Solaris 8 and csh shell

Thanks!

 

[PHV]

And what have you so far ?
And why insisting on csh ?

 

[eholdo]

The rest of the rather intricate script is in csh. As for so far, this is a new requirement, so I have an input filename and an output filename.... just need the rough direction as to which way to go, ie- sed, etc
Thanks!

 

[PHV]

man dd
man grep
By the way, if the pdf file is binary you're in trouble ...

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ222-2244

 

[eholdo]

Ok....why am I in trouble if it's a Binary pdf?
Thanks

 

[PHV]

Because most of the *nix file utilities are designed for text files.

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ222-2244

 

[eholdo]

I think I got by this by dd on the first 8 blocks and count =1 files=1 which gives me the first 8 blocks, which are straight text. Soooo, now I just need to figure out how to find the byte position of a character "%" in a file.

Any help is greatly appreciated!!