Need to print only the first line that has a match ...

[Tester_V]

Hi,
Need to print only the first line that has a match ...
I have a line in a file :
“ 2019-02-02 17:12:02.860,10552 ,Information," Test Program Name: Something else“
And the part of the line I need is - “Test Program Name: Something else”
I’d like to print only first line that matched the strings that have the same “ Test Program Name: “

And the same for this line:
“2019-02-02 17:12:02.865,10552 ,Information,"[LOT] Product: Something else"
I need only this part of the line - “Product: Something else”
I’d like to print only the first line that matches and ignore the rest of the lines that matched.
Thank you.

 

[ggriffit]

how are you processing the file ? are you using a loop to step through each line ?

For the checks you could either use a SPLIT type thing on the comma and then check the value returned in an array or perhaps use a RegEx.

Greg Griffiths
Livelink Certified Developer & ECM Global Star Champion 2005 & 2006

http://www.greggriffiths.org/livelink/

 

[Tester_V]

thank you for the reply!
I'm OK now. I just reloaded the file after I found the first match.
Thank you.