The file has teh folloowing contents.
PKG=VZevpsrc
NAME=Evoice Portal Application Software
VERSION=2.8
ARCH=SPARC_Sol_2.8
CATEGORY=application
CLASSES=none replacessi
BASEDIR=/tt
DESC=Update to approot.xml (05/24/2002)
I needto write a awk script which would intercatively ask the user for a version and description. So the script would ask.
Please enter a version no:
User:2.9
Please enter a description: Update to web.xml
Please eneter a date:06/11/2002.
After the user enters this information the file shoudl look like.
PKG=VZevpsrc
NAME=Evoice Portal Application Software
VERSION=2.9
ARCH=SPARC_Sol_2.8
CATEGORY=application
CLASSES=none replacessi
BASEDIR=/tt
DESC=Update to web.xml (06/11/2002)
Can anybody suggest a script.
PKG=VZevpsrc
NAME=Evoice Portal Application Software
VERSION=2.8
ARCH=SPARC_Sol_2.8
CATEGORY=application
CLASSES=none replacessi
BASEDIR=/tt
DESC=Update to approot.xml (05/24/2002)
I needto write a awk script which would intercatively ask the user for a version and description. So the script would ask.
Please enter a version no:
User:2.9
Please enter a description: Update to web.xml
Please eneter a date:06/11/2002.
After the user enters this information the file shoudl look like.
PKG=VZevpsrc
NAME=Evoice Portal Application Software
VERSION=2.9
ARCH=SPARC_Sol_2.8
CATEGORY=application
CLASSES=none replacessi
BASEDIR=/tt
DESC=Update to web.xml (06/11/2002)
Can anybody suggest a script.