This may seem rudimentary but if you wanted to find the valid host range of an address with 192.168.1.10/24 how would you do it?? It was a CCNA question I missed..
I can find if I know the subnet i.e. 255.255.255.224
Since the subnet mask (which is indicated by the /24) indicates the NETWORK portion of the address, and the question is asking for the HOST portion, you have the last 8 bits for host addresses.
Unless I'm missing something really easy, the available hosts for that address should be 192.168.1.1 thru 192.168.1.254
But the question should really have said 192.168.1.0/24, that's what has me wondering.
Maybe if you typed out the question exactly as it appears, we could be sure we're not misunderstanding.
It seem kinda like a trick question. If it's /24 then you don't have any bit mask since it is a Class C. So i think it would be in the 255.255.255.128 Subnet.
Do you happen to remember the choices they gave you?
This is a special notation (Shorthand) for CIDR (Classless InterDomain Routing) and classful addresses.
(Class A = /8, Class B = /16, and Class C = /24)
192.168.1.1/24.
IP Address : 198.168.1.1
Address Class : C
Network Address : 198.168.1.0
Subnet Address : 198.168.1.0
Subnet Mask : 255.255.255.0
Subnet bit mask : 110nnnnn.nnnnnnnn.nnnnnnnn.hhhhhhhh[/red]
Subnet Bits : 24
Host Bits : 8
Possible Number of Subnets : 1
Hosts per Subnet : 254
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