Need Help Translating Perl to PHP Syntax

[Solibra]

Hi all!

i'm about to translate a perl script to php.

i'm stuck with the following part of the script:

it checks within a db file if the client has already accessed this page before on the current day.

# Check if user's IP is already in the daily log files.
# If it is, then set firsttoday to false (0).
if(-e "count.access.log")
{
    open(LOG, &quot;<count.access.log&quot;);
    @ips = <LOG>;
    close(LOG);
    foreach $_ (@ips)
    {    
        if ($_ eq $userip . &quot;\n&quot;)
        {
            $firsttoday = 0;
        }
    }
}

Furthermore i need to set the current day in a variable. in perl it would look like this:

$today = (Sun, Mon, Tue, Wed, Thu, Fri, Sat, Sun)[(localtime)[6]];
            # Set to the current weekday.

How would this look in PHP?

I'd appreciate your help!

Maximilian

 

[skiflyer]

Here's the answer to the second part...

$today = date("l"

That'll be Sunday,Monday,Tuesday... though...

If you really want Sun,Mon,Tue,Wed... lemme know and I'll show you.

-Rob

Check out...

http://www.php.net/manual/en/function.date.php

for how to get more or different information from the date function.

 

[sleipnir214]

This script should be functionally equivalent:

if(file_exists("count.access.log&quot)
{
$ips = file ("count.access.log"
    foreach ($ips as $ip)
    {    
        if ($ip eq $userip . "\n&quot
        {
            $firsttoday = 0;
        }
    }
}


$today = date ("D" should work in replacement for your second question. Want the best answers? Ask the best questions:

http://www.catb.org/~esr/faqs/smart-questions.html

TANSTAAFL!

 

[Solibra]

i think i got it now!

thanks for taking the time guys!

Maximilian