NEC 2400 error message"-48V OVER CURRENT"

[bengi1234]

I have an NEC 2400 IPX. Every so often I get this error message -48V OVER CURRENT. Anyone have an idea what this means and should I be worried? Faulty card or something?

 

[belevedere]

Use CMD DFTD to read the messages. It will provide additional information on the error. Post it here.
In some cases this could just be someone plugging in a SLT into a MLT port, or some other analog device.

 

[bengi1234]

Thanks that is what I was reading. All it says is System Message 3-F (SUP) -48V over current and then a bunch of numbers, most of them zeros.

 

[bengi1234]

If a digital phone is defective could it cause this as well? The numbers must somehow equate to a lens number either way ... ?

 

[belevedere]

The "bunch of numbers" you mentioned are most likely hex code that can be read to find out which LEN is the problem. You need to post the entire error message for further evaluation. Or, you can get an Operations and maintenance manual and try to read the hex code.

 

[bengi1234]

Thanks Belvedere, I have the manuals but havent been able to find the page to decipher the code!

What I have figured out is: LP00-0-ACT means its in the first stack. Location of faulty circuit card (MG): 0; Location of faulty circuit card (U): 3; Location of faulty circuit card (G): 8. So this is module group 0, Unit 3, Group 8.

Then in the 'bunch of numbers' it says 1: 68 and then fourteen 0's. All the others (2-8) all give 16 0's as well. From what I can tell this must be narrowing it down to the port or lens number but I can't tell how to go further in.

 

[belevedere]

That is as far as you can take it. follow the LEN to the station jack.

 

[bengi1234]

The 68 throws me. lens numbers never go above 7 on the last digit. I can follow through to the line card in slot 8, I guess. What does the 68 mean? Should I check all the phones on the card or is there a way to narrow further? I really appreciate your help btw

 

[bengi1234]

OK so I'll answer my own question after more research in case anyone else ever follows this post ... the 68 is a hex number. You have to convert this to binary and then convert that to regular numbers. If there is a more confusing way to do it I'm sure it would have been used, but they did a pretty good job!