nawk syntax

[ac325ci]

in nawk can u do
a

if pattern1 and pattern2 found and not pattern4 and pattern5 are present;
print something..

so far i have

if ( /pattern1/ || /pattern2/ ) && ( ! /pattern3/ ) ...

this doesnt seem to work..

basically im trying to find pattern1 and 2.. but if pattern3 and 4 are also present then ignore it.. kinda like grepping for pattern1 and pattern2 but grep -v pattern3 and 4 out of it.. thanks in advance..

 

[feherke]

Hi

First of all your code has a syntax problem :

if [red]([/red]( /pattern1/ || /pattern2/ ) && ( ! /pattern3/ )[red])[/red] [gray]...[/gray]

But I think this is what you want :

if ( /pattern1/ && /pattern2/ && !/pattern3/ && !/pattern4/ ) [gray]...[/gray]

Feherke.

http://rootshell.be/~feherke/