n1=1 n2=2 tot=n1+n2; printf("%f"

[OOzy]

n1=1
n2=2
tot=n1+n2;
printf("%f",n1);
printf(" - "
printf("%f",n2);
printf(" = "
printf("%f",tot);

The above code should print

2 + 1 = 3

But I am using too many printfs. How can combine all the printfs into one printf

 

[ONIN]

n1=1,
n2=2;
tot=n1+n2;

printf("%f + %f = %f",&n1,&n2,&tot);

this is better way....
Tom

 

[rbobbitt]

Assuming, of course, that n1 and n2 are either type float or double.

Russ
bobbitts@hotmail.com

http://home.earthlink.net/~bobbitts

 

[aphrodita]

I thought it should be like this:

...
printf("%f + %f = %f",n1,n2,tot);
...
Best Regards,

aphrodita@mail.krovatka.ru {uiuc rules}

http://www.hellforge.org

 

[rbobbitt]

aphrodita's example is correct. You shouldn't pass printf() a pointer to the variables, as in Tom's example.

Russ
bobbitts@hotmail.com

http://home.earthlink.net/~bobbitts

 

[Lim]

Generaly, you can pas a pointer, why not.
But it will print value of a pointer.

 

[Cagliostro]

As I see, n2, n2, tot are integers. In this case you better is:
printf("%d + %d = %d",n1,n2,tot); John Fill

ivfmd@mail.md

 

[rbobbitt]

Lim:
It'll print the pointers by accident. Type float is not necessarily compatible with the address of a pointer. The %p modifier would be appropriate if you wanted the address of a pointer. At any rate, that wouldn't produce the desired results.

John:
Where did you get the idea that the variables are type int?

Russ
bobbitts@hotmail.com

http://home.earthlink.net/~bobbitts

 

[aphrodita]

John is right,
by looking at the output OOzy wants to get, he or she need ints. Best Regards,

aphrodita@mail.krovatka.ru {uiuc rules}

http://www.hellforge.org

 

[rbobbitt]

ints would be a more logical choice, but floats would be perfectly fine too.

Russ
bobbitts@hotmail.com

http://home.earthlink.net/~bobbitts

 

[ManasBehera]

n1=1;
n2=2;
tot=n1+n2;

printf("%f + %f = %f",n1,n2,tot);

It should work.....