Mod Calculation with an Array

[Jodi999]

I am looking to take:

INT32 num[45];
INT32 mod[3];
INT32 ans[4];

(the num and mod arrays get set to values here)

I've tried:
ans = num % mod;
&ans[0] = (INT32*)(num & mod);

...but can't get it to work. Is it possible to do a mod calculation using arrays for all of the operands?

 

[sedj]

Well you are trying to take a modulus between two arrays, which doesn't really make sense.

Maybe this will give you an idea of what you can do :

int main() {
        int arr[2];
        int arr2[2];

        arr2[0] = 52;
        arr2[1] = 2;

        arr[0] = arr2[0] % arr2[1];
        arr[1] = arr2[0] / arr2[1];
        printf("\nArr[0] is %i", arr[0]);
        printf("\nArr[1] is %i \n", arr[1]);
}

--------------------------------------------------
Free Database Connection Pooling Software

http://www.primrose.org.uk