Message for ARGV[2]????

[csd]

I used ARGVs for a awk program and it worked well but
it always had some messages like this:

"awk: Cannot find or open file abc...
....The file is abc..."

The command for the awk job I used was
awk -f test.awk test.txt abc

Here, ARGV[0] should be awk, [1] test.txt, which is indeed a file, but ARGV[2]=abc is not a file.
If I print ARGV[2] in the awk, it's really abc...and it could be used in the awk program for data processing...
It looked like just a warning message because everything
else is fine, any idea?

Thanks.
csd

 

[csd]

My question also is:
If it's just a warning message, is there any way I can
avoid it to appear?
Thanks.
csd

 

[flogrr]

Hi csd,

Try this:

awk -f test.awk test.txt -v var="abc"

replacing var with whatever variable name you want
to use in your awk script.

You may also want to use nawk instead of awk if you
have it on your machine.

Gawk ( GNU awk ) will also work if you have it.

HTH


flogrr
flogr@yahoo.com

 

[ruxshin]

Hi csd,

I think you're trying to pass arguments into the awk script right?

Try this if you're passing arguments into the awk script:
awk -f awkscript argName=argValue inputfile

So in your case:
awk -f test.awk song=abc test.txt

You can have as many args as you like, but they should be placed before the inputfile argument. Their values also must not contain spacing. The argument that you passed into the awk script can be accessed directly using the argument's name.

Hope the explanations will help you.

ruxshin

 

[csd]

ruxshin and flogrr:

I have already tested ruxshin's suggestion. I used 25 argvs, which are needed for my project, the job worked very good and the screen was very "cean": There was no warning message on it.

I think flogrr's way would also work and i will have time to test it later...
Great thanks to both of you.


csd