Memory confusion 1

[KenCunningham]

Hi folks, I have A V880 with (ostensibly) 4 Gb Memory. However, prtdiag -v gives me the following output (sorry if it's a bit garbled in the pasting):

Logical Logical Logical
MC Bank Bank Bank DIMM Interleave Interleaved
Brd ID num size Status Size Factor with
---- --- ---- ------ ----------- ------ ---------- -----------
A 0 0 512MB no_status 256MB 8-way 0
A 0 1 512MB no_status 256MB 8-way 0
A 0 2 512MB no_status 256MB 8-way 0
A 0 3 512MB no_status 256MB 8-way 0
A 2 0 512MB no_status 256MB 8-way 0
A 2 1 512MB no_status 256MB 8-way 0
A 2 2 512MB no_status 256MB 8-way 0
A 2 3 512MB no_status 256MB 8-way 0

It seems to be telling me that the machine has only 2 Gb memory made up of 8 256 Mb DIMMs. On the other hand, the 'Logical Bank Size' indicates 8 512 Mb, giving me my 4 Gb. prtdiag -v also correctly reports 4 Gb. Can anyone shed any light on the difference between the DIMM size and the 'Logical Bank Size', please? TIA.

 

[Annihilannic]

Presumably each bank of memory consists of two 256MB DIMMs, so you have in fact 16 DIMMs in the machine.

Annihilannic.

 

[KenCunningham]

Annihilannic, that's the only logical explanation I can think of too - many thanks for your input.

 

[julianbarnett]

You probably have this already - I find it easier to interpret than prtdiags should work for most hardware - needs Perl.

http://myweb.cableone.net/4schmidts/memconf.html