matching a pattern with awk 1

[MoshiachNow]

HI,

I'd like to print lines that match pattern "AB" and do not match pattern "CD".

Something like:

awk '/AB/ && /!~ CD/ {print $0}'

What is the correct syntax ?
Thanks

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[PHV]

Try something like this:
awk '/AB/{if($0!~/CD/)print}'

Hope This Help, PH.
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[MoshiachNow]

Great,thanks

awk '/AB/ && $0 !~ /CD/ {print $4}'

Also works.

"Long live king Moshiach !"

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[Ygor]

Also try...

awk '/AB/ && !/CD/ {print $4}'

 

[stefanwagner]

cat FILE | grep AB | grep -v CD

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