<xsl:stylesheet xmlns:xsl="http://www.w3.org/TR/WD-xsl">

[dionisox]

I have a xls that use <xsl:stylesheet xmlns:xsl=&quot;

http://www.w3.org/TR/WD-xsl&quot;>

How can i test if a node is not a child of another node, if a node has a parent node called xxx.......?
The sintax i usually use give me only error.

Thanks

 

[Nosferatu]

Try to add to your stylesheet the XSLT namespace, something like:

<xsl:stylesheet xmlns:xsl=&quot;[URL unfurl="true"]http://www.w3.org/TR/WD-xsl&quot;[/URL]
xmlns:xslt=&quot;[URL unfurl="true"]http://www.w3.org/1999/XSL/Transform&quot;>[/URL]
>

then use the usual xslt functions for that.
Or... would that be in the XPath language? However, try this.
I am also interested in this namespace trouble, so I am curious about other replies. [red]Nosferatu[/red]
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