ls with optional char

[jriggs420]

Hi all,

This works

ls joe/home/*"$*"

fine as a shell script. But how can I tell the shell to also return files which are optionally followed by a single letter, 'x' for example. I think using another wildcard will make this regex too greedy, TIA

Because a thing seems difficult for you, do not think it impossible for anyone to accomplish.
Marcus Aurelius

 

[SamBones]

How about...

ls joe/home/*"$*" joe/home/*x

If that doesn't do it, you might need to better define what you're looking for.

 

[PHV]

My guess:
ls joe/home/*"$*" joe/home/*"$*"x 2>/dev/null

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ181-2886

 

[jriggs420]

Thanks for the tips guys, that's pretty close to what I was getting at, but not quite it. Maybe a little more info would help clarify what I'm really after.
suppose the directory in question has these files:
111 111x 111xx 111pp 111qqq. How can I list only the files
111 111x. Basically, I want the file with '111' and any file(s) which is optionally followed by a single 'x' (or really any character). Incidently I'm in csh, if that matters, thanks again, Joe

Because a thing seems difficult for you, do not think it impossible for anyone to accomplish.
Marcus Aurelius

 

[PHV]

ls $1 ${1}x 2>/dev/null

Hope This Helps, PH.
Want to get great answers to your Tek-Tips questions? Have a look at FAQ219-2884 or FAQ181-2886

 

[SamBones]

How about this...

#/bin/ksh

for FX in *[!x]x
do
    F=${FX%x}
    [[ -f $F ]] && ls $F
    ls $FX
done

This only lists files with a single "x" at the end and it's non-x-ending counterpart. It would list [tt]111[/tt] and [tt]111x[/tt].

 

[PHV]

Sam, I thought that 111 was the value of $1 ...

 

[mrregan]

ls 111 111?

 

[stefanwagner]

ls * | egrep 111[x]?$
ls * | egrep $1[$2]?$

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