ls command selection 1

[imFrank]

I'm using ls & awk to generate a (small) numbered list of files ending in .art. Rather than having the user enter the long filename, I want to pick a number and pass the respective filename on to the next command. Here's what I have so far:

ls -lh *.art | awk '{ print NR, ":\t", $5, "\t",$6, $7 $8, $9 }'

The output looks like:

1 : 1.4G Mar 3008:46 2005_035155903000000c004.art
2 : 402M Mar 3008:44 2005_036234503000000c004.art
3 : 88M Mar 3008:44 2005_037133003000000x004.art

Enter .art file number (1, 2, 3...):

I'm using: "set INPUT = $<" to capture the users choice (1, 2, or 3...) but how can I use awk to convert the users choice to the respective filename to pass to the next command?

Where the next command would be something like:

read_art_file $INPUT

Thanks,
Frank

 

[Ygor]

The question is more suited to the UNIX Scripting Forum forum822.

You don't day which shell you are using. This is bash, but should work for ksh too...

#!/usr/bin/bash

oldIFS=$IFS
IFS='
'
PS3='Enter .art file number: '
select i in $(ls -lh *.art|awk '{print $5,$6,$7,$8,$9}')
do
  if [[ $i ]]
  then
    echo Number selected: $REPLY
    echo File selected: $(echo $i|awk '{print $5}')
    break
  fi
done
IFS=$oldIFS